LeetCode in Kotlin

997. Find the Town Judge

Easy

In a town, there are n people labeled from 1 to n. There is a rumor that one of these people is secretly the town judge.

If the town judge exists, then:

1. The town judge trusts nobody.
2. Everybody (except for the town judge) trusts the town judge.
3. There is exactly one person that satisfies properties 1 and 2.

You are given an array trust where trust[i] = [ai, bi] representing that the person labeled ai trusts the person labeled bi. If a trust relationship does not exist in trust array, then such a trust relationship does not exist.

Return the label of the town judge if the town judge exists and can be identified, or return -1 otherwise.

Example 1:

Input: n = 2, trust = [[1,2]]

Output: 2

Example 2:

Input: n = 3, trust = [[1,3],[2,3]]

Output: 3

Example 3:

Input: n = 3, trust = [[1,3],[2,3],[3,1]]

Output: -1

Constraints:

• 1 <= n <= 1000
• 0 <= trust.length <= 104
• trust[i].length == 2
• All the pairs of trust are unique.
• ai != bi
• 1 <= ai, bi <= n

Solution

class Solution {
    fun findJudge(n: Int, trust: Array<IntArray>): Int {
        val count = IntArray(n + 1)
        for (t in trust) {
            --count[t[0]]
            ++count[t[1]]
        }
        for (i in 1 until n + 1) if (count[i] == n - 1) return i
        return -1
    }
}

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