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‎Structure/Practice/Qs_56.c‎

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// Enter address (house no, block, city, state) of 5 people
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#include <stdio.h>
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typedef struct people_details
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{
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char name[20];
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char house_no[20];
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char block[40];
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char city[20];
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char state[20];
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int postal_code;
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} log;// alias of sturct people_details
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void initialscanInfo (int *n)
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{
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printf("How many people's address do you want to save : ");
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scanf("%d", &(*n));
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getchar();// for consuming newline character from the buffer
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}
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void scanInfo (log *people, int n)
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{
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for (int i = 0; i < n; i++)
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{
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printf("Stranger's Information: %d\n\n", i+1);
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printf("Name: ");
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fgets(people[i].name, sizeof(people->name), stdin);
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printf("House no: ");
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fgets(people[i].house_no, sizeof(people->house_no), stdin);
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printf("Block: ");
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fgets(people[i].block, sizeof(people->block), stdin);
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printf("City: ");
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fgets(people[i].city, sizeof(people->city), stdin);
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printf("State: ");
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fgets(people[i].state, sizeof(people->state), stdin);
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printf("Postal code: ");
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scanf("%d", &people[i].postal_code);
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getchar();// Consumes newline character after the integer input
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}
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}
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void printInfo (log people[], int n)
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{
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for (int i = 0; i < n; i++)
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{
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printf("Stranger's Information: %d\n\n", i+1);
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printf("Stranger's name: %s", people[i].name);
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printf("Stranger's house no : %s", people[i].house_no);
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printf("Stranger's block: %s", people[i].block);
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printf("Stranger's city: %s", people[i].city);
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printf("Stranger's state: %s", people[i].state);
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printf("Stranger's postal code: %d\n\n", people[i].postal_code);
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}
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}
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int main ()
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{
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int n;//number of person
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initialscanInfo(&n);
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log person[n];
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scanInfo(person, n);//takes input
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printInfo(person, n);//prints address
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return 0;
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}

‎Structure/Practice/Qs_57.c‎

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// Create a structure to store vectors. then make a fucntion to return sum of 2 vectors
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// important
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#include <stdio.h>
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typedef struct vectors
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{
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float x;
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float y;
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float sum;
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} vec;
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void scanInfo (vec *vector, vec *vector2)
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{
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scanf("%f%f", &vector->x, &vector->y);
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scanf("%f%f", &vector2->x, &vector2->y);
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}
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void vector_summation (vec vector1, vec vector2, vec sum)
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{
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sum.x = vector1.x+vector2.x;
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sum.y = vector1.y+vector2.y;
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printf("Sum of x = %0.2f\nSum of y = %0.2f\n", sum.x, sum.y);
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}
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int main ()
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{
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vec vector1, vector2;
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vec sum = {0};
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scanInfo(&vector1, &vector2);
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vector_summation(vector1, vector2, sum);
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return 0;
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}
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/*
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vector 1 = Xi + Yj
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vector 2 = X'i + Y'j
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sum of vector 1 and 2 = (X+X')i + (Y+Y')j (sum of both axis in icap and jcap)
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*/

‎Structure/Practice/Qs_58.c‎

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// Create a structure to store complex number (use arrow operator)
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#include <stdio.h>
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typedef struct complex
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{
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int real;
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char operator;
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int imaginary;
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} com;
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void scanInfo (com *number)
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{
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printf("Real Number: ");
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scanf("%d", &number->real);
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getchar();// cosumes newline character from buffer
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printf("Operator: ");
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scanf("%c", &number->operator);
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printf("Imaginary Number: ");
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scanf("%d", &number->imaginary);
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}
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void printInfo (com number)
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{
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printf("Complex number: %d%c%di\n", number.real, number.operator, number.imaginary);
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}
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int main ()
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{
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com number1;
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scanInfo(&number1);
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printInfo(number1);
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return 0;
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}

‎Structure/Practice/Qs_59.c‎

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/* Theoretical Question
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You have to store the marks of 30 students in class
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What will you use?
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a. array of 30 floats
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b. sturcture
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ans: a bcause we just have to store marks of 30 students so it better
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to choose array of 30 floats, but we can use both, we use structure to
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store different types of data, but here we are storing only one type.
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*/
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// array of 30 floats
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#include <stdio.h>
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int main ()
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{
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float numbers[30] = {12.2, 21.3, 49.3, 19.9, 34, 34, 12, 23, 34, 43.3,
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13.1, 29.5, 30, 12.3, 38, 10.4, 43.1, 12, 21, 12,
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45, 2, 0, 12, 43, 19.4, 12, 23, 12, 21};
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for (int i = 0; i < 30; i++)
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{
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printf("%dth student's mark: %0.1f\n", i+1, numbers[i]);
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}
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return 0;
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}

‎Structure/Practice/Qs_60.c‎

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// Make a structure to store Bank Account Information of a customer of ABC Bank. Also, make an alias for it.
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#include <stdio.h>
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typedef struct account
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{
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char account_number[20];
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char account_type[10];
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char key[10];
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char name[20];
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char blood[10];
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char nid[20];
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char phone[20];
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char address[50];
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char profession[20];
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char nominee_name[20];
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char nominee_blood[10];
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char nominee_nid[20];
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char nominee_phone[20];
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char nominee_profession[10];
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char nominee_relation[10];
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int credit_history;
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} data;
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void printInfo (data customer)
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{
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printf("Customer details :\n\n");
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printf("Account no : %s\n", customer.account_number);
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printf("Account type : %s\n", customer.account_type);
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printf("Account key : %s\n", customer.key);
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printf("Account holder name : %s\n", customer.name);
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printf("Account holder blood group : %s\n", customer.blood);
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printf("Account holder nid no : %s\n", customer.nid);
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printf("Account holder phone no : %s\n", customer.phone);
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printf("Account holder address : %s\n", customer.address);
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printf("Account holder profession : %s\n", customer.profession);
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printf("Account nominee name : %s\n", customer.nominee_name);
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printf("Account nominee blood group : %s\n", customer.nominee_blood);
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printf("Account nominee nid no : %s\n", customer.nominee_nid);
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printf("Account nominee phone no : %s\n", customer.nominee_phone);
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printf("Account nominee profession : %s\n", customer.nominee_profession);
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printf("Account nominee relation : %s\n", customer.nominee_relation);
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printf("Account holder credit history : %d credit\n", customer.credit_history);
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}
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int main ()
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{
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data customer1 = {"ABC12094354", "Regular", "ky2#1@8*z", "Nazmus Sakib", "A+", "45123413121", "(+880)1881296235", "65/5 Kadamtala, East Basabo, Dhaka-1214", "Software Engineer",
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"Umme Kulsum", "AB+", "49213845320", "+8801907232841", "Housewife", "Mother", 180 };
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printInfo(customer1);
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return 0;
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}

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